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Current Electricity question

2024 · 4 Apr · Shift 1 · Q89
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Current Electricity question

2024 · 4 Apr · Shift 1 · Q89

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
Twelve wires each having resistance 2Ω2 \Omega2Ω are joined to form a cube. A battery of 6 V6 \mathrm{~V}6 V emf is joined across point aaa and ccc. The voltage difference between eee and fff is ‾\underline{\hspace{2cm}}​ V. JEE Main 2024 (Online) 4th April Morning Shift Physics - Current Electricity Question 37 English
Numerical answer
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