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Current Electricity question

2022 · 27 Jul · Shift 1 · Q57
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  5. /2022 · 27 Jul · Shift 1 · Q57

Current Electricity question

2022 · 27 Jul · Shift 1 · Q57

JEE MainPhysicsCurrent ElectricityMCQ+4 / −1
Two sources of equal emfs are connected in series. This combination is connected to an external resistance R. The internal resistances of the two sources are r1r_{1}r1​ and r2r_{2}r2​ (r1>r2)\left(r_{1}>r_{2}\right)(r1​>r2​). If the potential difference across the source of internal resistance r1r_{1}r1​ is zero, then the value of R will be :
  1. A
    r1−r2r_{1}-r_{2}r1​−r2​
  2. B
    r1r2r1+r2\frac{r_{1} r_{2}}{r_{1}+r_{2}}r1​+r2​r1​r2​​
  3. C
    r1+r22\frac{r_{1}+r_{2}}{2}2r1​+r2​​
  4. D
    r2−r1r_{2}-r_{1}r2​−r1​
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