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Current Electricity question

2022 · 27 Jun · Shift 2 · Q69
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Current Electricity question

2022 · 27 Jun · Shift 2 · Q69

JEE MainPhysicsCurrent ElectricityNumerical+4 / −1
In the given circuit 'a' is an arbitrary constant. The value of m for which the equivalent circuit resistance is minimum, will be x2\sqrt {{x \over 2}}2x​​. The value of x is ‾\underline{\hspace{2cm}}​. JEE Main 2022 (Online) 27th June Evening Shift Physics - Current Electricity Question 158 English
Numerical answer
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Correct answer: 3

The question refers to a circuit and asks for the value of mmm for which the equivalent resistance is minimum, with the result given as m=x2.m=\sqrt{\frac{x}{2}}.m=2x​​. We are asked to find xxx.

However, the actual circuit diagram is not provided in the prompt. Without the circuit, the equivalent resistance cannot be derived uniquely from first principles.

Given the stored correct answer is 333, let us interpret what that implies.

If m=x2,m=\sqrt{\frac{x}{2}},m=2x​​, and the intended result from the circuit minimization is likely m=32,m=\sqrt{\frac{3}{2}},m=23​​, then comparing, x2=32  ⟹  x=3.\sqrt{\frac{x}{2}}=\sqrt{\frac{3}{2}} \implies x=3.2x​​=23​​⟹x=3.

So the required value is 3.\boxed{3}.3​.

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