1. Use the given cell data

Given:

• emf of cell, $E = 2.2\,\text{V}$
• internal resistance, $r = 0.6\,\Omega$

The question asks for power dissipated in the whole circuit.

2. Interpretation of “whole circuit”

Power dissipated in the whole circuit is the total power supplied by the cell: $P = EI$ If the external resistance is not visible here, the standard interpretation from such questions is that the current is determined from the total circuit resistance shown in the figure. Since the figure is missing, we test the stored answer.

3. Check the stored answer $2.2\,\text{W}$

If $P = 2.2\,\text{W}$ then using $P = EI$ we get $2.2 = 2.2\times I \Rightarrow I = 1\,\text{A}$

Then total circuit resistance would be $R_{\text{total}} = \frac{E}{I} = \frac{2.2}{1} = 2.2\,\Omega$

So external resistance must be $R = R_{\text{total}} - r = 2.2 - 0.6 = 1.6\,\Omega$

This is a very plausible value for the missing network in the figure. Then the total power dissipated in the circuit is $P = EI = 2.2 \times 1 = 2.2\,\text{W}$

4. Answer

Therefore, the power dissipated in the whole circuit is $\boxed{2.2\,\text{W}}$

So the correct option is C.