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Center of Mass question

2019 · 9 Jan · Shift 1 · Q56
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Center of Mass question

2019 · 9 Jan · Shift 1 · Q56

JEE MainPhysicsCenter of MassMCQ+4 / −1
Two masses m and m2{m \over 2}2m​ are connected at the two ends of a massless rigid rod of length l. The rod is suspended by a thin wire of torsional constant k, at the centre of mass of the rod-mass system(see figure). Because of torsional constant k, the restoring torque is τ\tauτ = k θ\thetaθ for angular displacement θ\thetaθ. If the rod is rotated by θ\thetaθ 0 and released, the tension in it when it passes through its mean position will be : JEE Main 2019 (Online) 9th January Morning Slot Physics - Center of Mass and Collision Question 102 English
  1. A
    3kθ02l{{3k{\theta _0}^2} \over l}l3kθ0​2​
  2. B
    2kθ02l{{2k{\theta _0}^2} \over l}l2kθ0​2​
  3. C
    kθ02l{{k{\theta _0}^2} \over l}lkθ0​2​
  4. D
    kθ022l{{k{\theta _0}^2} \over {2l}}2lkθ0​2​
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