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Center of Mass question

2019 · 12 Jan · Shift 1 · Q59
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Center of Mass question

2019 · 12 Jan · Shift 1 · Q59

JEE MainPhysicsCenter of MassMCQ+4 / −1
The position vector of the centre of mass r→ cm \overrightarrow r {\,_{cm}}\,rcm​ of an asymmetric uniform bar of negligible area of crosssection as shown in figure is : JEE Main 2019 (Online) 12th January Morning Slot Physics - Center of Mass and Collision Question 97 English
  1. A
    r→cm =118L  x^+88Ly^{\overrightarrow r _{cm}}\, = {{11} \over 8}L\,\,\widehat x + {8 \over 8}L\widehat yrcm​=811​Lx+88​Ly​
  2. B
    r→cm =58L  x^+138Ly^{\overrightarrow r _{cm}}\, = {5 \over 8}L\,\,\widehat x + {{13} \over 8}L\widehat yrcm​=85​Lx+813​Ly​
  3. C
    r→cm =138L  x^+58Ly^{\overrightarrow r _{cm}}\, = {{13} \over 8}L\,\,\widehat x + {5 \over 8}L\widehat yrcm​=813​Lx+85​Ly​
  4. D
    r→cm =38L  x^+118Ly^{\overrightarrow r _{cm}}\, = {3 \over 8}L\,\,\widehat x + {{11} \over 8}L\widehat yrcm​=83​Lx+811​Ly​
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