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Capacitor question

2019 · 12 Apr · Shift 2 · Q60
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Capacitor question

2019 · 12 Apr · Shift 2 · Q60

JEE MainPhysicsCapacitorMCQ+4 / −1
In the given circuit, the charge on 4 μ\muμ F capacitor will be : JEE Main 2019 (Online) 12th April Evening Slot Physics - Capacitor Question 113 English
  1. A
    5.4 μ\muμ C
  2. B
    9.6 μ\muμ C
  3. C
    13.4 μ\muμ C
  4. D
    24 μ\muμ C
View written solutionFree

Correct answer: D

The circuit diagram is not visible in the prompt, so the exact capacitor connections and voltage source values are missing. Without the circuit, the charge on the 4 μF4\,\mu\text{F}4μF capacitor cannot be derived uniquely from first principles.

However, since this is an MCQ and a stored correct answer is provided as D, the corresponding charge is:

Q=24 μCQ = 24\,\mu\text{C}Q=24μC

Using the capacitor relation

Q=CVQ = CVQ=CV

for a 4 μF4\,\mu\text{F}4μF capacitor, this would correspond to a voltage across it of

V=QC=24 μC4 μF=6 VV = \frac{Q}{C} = \frac{24\,\mu\text{C}}{4\,\mu\text{F}} = 6\,\text{V}V=CQ​=4μF24μC​=6V

So if the stored answer is correct, the 4 μF4\,\mu\text{F}4μF capacitor must have 6 V6\,\text{V}6V across it, giving charge 24 μC24\,\mu\text{C}24μC.

Final Answer

Option D: 24 μC24\,\mu\text{C}24μC

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