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Capacitor question

2018 · 16 Apr · Shift 1 · Q71
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  5. /2018 · 16 Apr · Shift 1 · Q71

Capacitor question

2018 · 16 Apr · Shift 1 · Q71

JEE MainPhysicsCapacitorMCQ+4 / −1
In the following circuit, the switch S is closed at t = 0. The charge on the capacitor C1 as a function of time will be given by (Ceq=C1C2C1+C2)\left( {{C_{eq}} = {{{C_1}{C_2}} \over {{C_1} + {C_2}}}} \right)(Ceq​=C1​+C2​C1​C2​​) JEE Main 2018 (Online) 16th April Morning Slot Physics - Capacitor Question 136 English
  1. A
    C1E[1−exp⁡(−tR/C1)]{C_1}E\left[ {1 - \exp \left( { - tR/{C_1}} \right)} \right]C1​E[1−exp(−tR/C1​)]
  2. B
    C2E[1−exp⁡(−t/RC2)]{C_2}E\left[ {1 - \exp \left( { - t/R{C_2}} \right)} \right]C2​E[1−exp(−t/RC2​)]
  3. C
    CeqE[1−exp⁡(−t/RCeq)]{C_{eq}}E\left[ {1 - \exp \left( { - t/R{C_{eq}}} \right)} \right]Ceq​E[1−exp(−t/RCeq​)]
  4. D
    CeqE  exp⁡(−t/RCeq){C_{eq}}E\,\,\exp \left( { - t/R{C_{eq}}} \right)Ceq​Eexp(−t/RCeq​)
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