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Capacitor question

2019 · 12 Jan · Shift 2 · Q68
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  5. /2019 · 12 Jan · Shift 2 · Q68

Capacitor question

2019 · 12 Jan · Shift 2 · Q68

JEE MainPhysicsCapacitorMCQ+4 / −1
In the circuit shown, find C if the effective capacitance of the whole circuit is to be 0.5 μ\muμ F. All values in the circuit are in μ\muμ F. JEE Main 2019 (Online) 12th January Evening Slot Physics - Capacitor Question 123 English
  1. A
    65μF{6 \over 5}\mu F56​μF
  2. B
    711μF{7 \over 11}\mu F117​μF
  3. C
    4 μ\muμ F
  4. D
    710μF{7 \over 10}\mu F107​μF
View written solutionFree

Correct answer: B

The circuit diagram is not visible in the prompt, so the exact capacitor connections are missing. Without the actual arrangement of capacitors, the value of CCC cannot be derived uniquely from the given information alone.

However, since a stored correct answer is provided, I can only make a consistency check against the options:

  1. The required equivalent capacitance is 0.5 μF0.5\,\mu F0.5μF.
  2. Depending on the network, values like 65\dfrac{6}{5}56​, 711\dfrac{7}{11}117​, 444, and 710\dfrac{7}{10}107​ μF\mu FμF could all be plausible for an unknown branch capacitor.
  3. But without the circuit topology, there is no valid step-by-step reduction possible.

So, strictly speaking:

  • The problem is incomplete as stated because the circuit figure is required.
  • Hence the answer cannot be independently verified from first principles.

Given the stored correct answer, the marked option would be:

C=711 μF\boxed{C=\frac{7}{11}\,\mu F}C=117​μF​

which corresponds to Option B.

If you upload or describe the capacitor network, I can solve it properly step-by-step and verify whether 711 μF\dfrac{7}{11}\,\mu F117​μF is indeed correct.

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