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Atoms and Nuclei question

2023 · 12 Apr · Shift 1 · Q67

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JEE Main
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Atoms and Nuclei
2023 · 12 Apr · Shift 1 · Q67

Atoms and Nuclei question

2023 · 12 Apr · Shift 1 · Q67

JEE MainPhysicsAtoms and NucleiNumerical+4 / −1

A common example of alpha decay is

{ }_{92}^{238} \mathrm{U} \longrightarrow{ }_{90}^{234} \mathrm{Th}+{ }_{2} \mathrm{He}^{4}+\mathrm{Q}

Given :

{ }_{92}^{238} \mathrm{U}=238.05060 ~\mathrm{u}

,

{ }_{90}^{234} \mathrm{Th}=234.04360 ~\mathrm{u}

,

{ }_{2}^{4} \mathrm{He}=4.00260 ~\mathrm{u}

and

1 \mathrm{u}=931.5 \frac{\mathrm{MeV}}{c^{2}}

The energy released

(Q)

during the alpha decay of

{ }_{92}^{238} \mathrm{U}

is

\underline{\hspace{2cm}}

MeV

Numerical answer

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