JEE MainPhysicsAtoms and NucleiMCQ+4 / −1
If the series limit frequency of the Lyman series is , then the series limit frequency of the Pfund series is:
- A
- B
- C
- D
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Correct answer: A
- Use the hydrogen spectral frequency formula
For hydrogen, the frequency of a spectral line is
u = cR\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right), \qquad n_2>n_1$$ For the **series limit**, $n_2 \to \infty$, so $$\nu_{\text{limit}} = cR\left(\frac{1}{n_1^2}-0\right)=\frac{cR}{n_1^2}$$ 2. **Lyman series limit** For the Lyman series, $n_1=1$. So, $$\nu_L = \frac{cR}{1^2}=cR$$ 3. **Pfund series limit** For the Pfund series, $n_1=5$. Hence, $$\nu_P = \frac{cR}{5^2}=\frac{cR}{25}$$ Using $\nu_L=cR$, $$\nu_P = \frac{\nu_L}{25}$$ 4. **Match with options** Thus the correct option is $$\boxed{\frac{\nu_L}{25}}$$ So, **Option A** is correct.More from Atoms and Nuclei
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