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Alternating Current question

2025 · 24 Jan · Shift 1 · Q69

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JEE Main
Physics
Alternating Current
2025 · 24 Jan · Shift 1 · Q69

Alternating Current question

2025 · 24 Jan · Shift 1 · Q69

JEE MainPhysicsAlternating CurrentMCQ+4 / −1

An alternating current is given by

\mathrm{I}=\mathrm{I}_{\mathrm{A}} \sin \omega \mathrm{t}+\mathrm{I}_{\mathrm{B}} \cos \omega \mathrm{t}

. The r.m.s current will be

A
$\frac{\sqrt{\mathrm{I}_{\mathrm{A}}^2+\mathrm{I}_{\mathrm{B}}^2}}{2}$
B
$\sqrt{\frac{\mathrm{I}_{\mathrm{A}}^2+\mathrm{I}_{\mathrm{B}}^2}{2}}$
C
$\frac{\left|\mathrm{I}_{\mathrm{A}}+\mathrm{I}_{\mathrm{B}}\right|}{\sqrt{2}}$
D
$\sqrt{\mathrm{I}_{\mathrm{A}}^2+\mathrm{I}_{\mathrm{B}}^2}$

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