1. Given data

• Resistance: $R = 110\,\Omega$
• Supply voltage: $V_{\text{rms}} = 220\,\text{V}$
• Angular frequency: $\omega = 300\,\text{rad/s}$

We need the rms current in the original series LCR circuit.

2. Case 1: Capacitor removed

Then the circuit becomes a series RL circuit.

Given: current lags voltage by $45^\circ$.

For an RL circuit,

with $\phi = 45^\circ$.

So,

3. Case 2: Inductor removed

Then the circuit becomes a series RC circuit.

Given: current leads voltage by $45^\circ$.

For an RC circuit,

where the phase magnitude is $45^\circ$.

Thus,

4. Original LCR circuit

In the original series LCR circuit,

But we found

Hence,

So the impedance is

5. Current in the circuit

Using

we get

6. Option check

• A: $1\,\text{A}$ ❌
• B: $2.5\,\text{A}$ ❌
• C: $2\,\text{A}$ ✅
• D: $1.5\,\text{A}$ ❌

Therefore, the correct answer is Option C.