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Vector Algebra question

2022 · 25 Jun · Shift 2 · Q42
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  5. /2022 · 25 Jun · Shift 2 · Q42

Vector Algebra question

2022 · 25 Jun · Shift 2 · Q42

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let b→=i^+j^+λk^\overrightarrow b = \widehat i + \widehat j + \lambda \widehat kb=i+j​+λk, λ∈\lambda\inλ∈ R. If a→\overrightarrow aa is a vector such that a→×b→=13i^−j^−4k^\overrightarrow a \times \overrightarrow b = 13\widehat i - \widehat j - 4\widehat ka×b=13i−j​−4k and a→ . b→+21=0\overrightarrow a \,.\,\overrightarrow b + 21 = 0a.b+21=0, then (b→−a→). (k^−j^)+(b→+a→). (i^−k^)\left( {\overrightarrow b - \overrightarrow a } \right).\,\left( {\widehat k - \widehat j} \right) + \left( {\overrightarrow b + \overrightarrow a } \right).\,\left( {\widehat i - \widehat k} \right)(b−a).(k−j​)+(b+a).(i−k) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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