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Vector Algebra question

2022 · 27 Jul · Shift 2 · Q40
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  5. /2022 · 27 Jul · Shift 2 · Q40

Vector Algebra question

2022 · 27 Jul · Shift 2 · Q40

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let a→\overrightarrow aa, b→\overrightarrow bb, c→\overrightarrow cc be three non-coplanar vectors such that a→×b→\overrightarrow a \times\overrightarrow ba×b = 4 c→\overrightarrow cc, b→×c→\overrightarrow b \times\overrightarrow cb×c = 9 a→\overrightarrow aa and c→×a→\overrightarrow c \times\overrightarrow ac×a=αb→\alpha\overrightarrow bαb, α\alphaα> 0. If ∣a→∣+∣b→∣+∣c→∣=136\left| {\overrightarrow a } \right| + \left| {\overrightarrow b } \right| + \left| {\overrightarrow c } \right| = {1 \over {36}}​a​+​b​+​c​=361​, then α\alphaα is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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