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Vector Algebra question

2022 · 25 Jun · Shift 1 · Q40
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  5. /2022 · 25 Jun · Shift 1 · Q40

Vector Algebra question

2022 · 25 Jun · Shift 1 · Q40

JEE MainMathematicsVector AlgebraNumerical+4 / −1
Let θ\thetaθ be the angle between the vectors a→\overrightarrow aa and b→\overrightarrow bb, where ∣a→∣=4,∣b→∣=3|\overrightarrow a | = 4,|\overrightarrow b | = 3∣a∣=4,∣b∣=3 and θ∈(π4,π3)\theta \in \left( {{\pi \over 4},{\pi \over 3}} \right)θ∈(4π​,3π​). Then ∣(a→−b→)×(a→+b→)∣2+4(a→ . b→)2{\left| {\left( {\overrightarrow a - \overrightarrow b } \right) \times \left( {\overrightarrow a + \overrightarrow b } \right)} \right|^2} + 4{\left( {\overrightarrow a \,.\,\overrightarrow b } \right)^2}​(a−b)×(a+b)​2+4(a.b)2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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