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Sequences and Series question

2024 · 6 Apr · Shift 1 · Q56
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Sequences and Series question

2024 · 6 Apr · Shift 1 · Q56

JEE MainMathematicsSequences and SeriesNumerical+4 / −1
Let the first term of a series be T1=6T_1=6T1​=6 and its rth r^{\text {th }}rth  term Tr=3Tr−1+6r,r=2,3T_r=3 T_{r-1}+6^r, r=2,3Tr​=3Tr−1​+6r,r=2,3, ............ nnn. If the sum of the first nnn terms of this series is 15(n2−12n+39)(4⋅6n−5⋅3n+1)\frac{1}{5}\left(n^2-12 n+39\right)\left(4 \cdot 6^n-5 \cdot 3^n+1\right)51​(n2−12n+39)(4⋅6n−5⋅3n+1), then nnn is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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