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Sequences and Series question

2024 · 5 Apr · Shift 2 · Q55
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  5. /2024 · 5 Apr · Shift 2 · Q55

Sequences and Series question

2024 · 5 Apr · Shift 2 · Q55

JEE MainMathematicsSequences and SeriesNumerical+4 / −1
If 1+3−223+5−2618+93−112363+49−206180+…1+\frac{\sqrt{3}-\sqrt{2}}{2 \sqrt{3}}+\frac{5-2 \sqrt{6}}{18}+\frac{9 \sqrt{3}-11 \sqrt{2}}{36 \sqrt{3}}+\frac{49-20 \sqrt{6}}{180}+\ldots1+23​3​−2​​+185−26​​+363​93​−112​​+18049−206​​+… upto ∞=2+(ba+1)log⁡e(ab)\infty=2+\left(\sqrt{\frac{b}{a}}+1\right) \log _e\left(\frac{a}{b}\right)∞=2+(ab​​+1)loge​(ba​), where a and b are integers with gcd⁡(a,b)=1\operatorname{gcd}(a, b)=1gcd(a,b)=1, then 11a+18b\mathrm{11 a+18 b}11a+18b is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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