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Probability question

2021 · 24 Feb · Shift 1 · Q44
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  5. /2021 · 24 Feb · Shift 1 · Q44

Probability question

2021 · 24 Feb · Shift 1 · Q44

JEE MainMathematicsProbabilityNumerical+4 / −1
Let Bi (i = 1, 2, 3) be three independent events in a sample space. The probability that only B1 occur is α\alphaα, only B2 occurs is β\betaβ and only B3 occurs is γ\gammaγ. Let p be the probability that none of the events Bi occurs and these 4 probabilities satisfy the equations (α−2β)p=αβ\left( {\alpha - 2\beta } \right)p = \alpha \beta(α−2β)p=αβ and (β−3γ)p=2βγ\left( {\beta - 3\gamma } \right)p = 2\beta \gamma(β−3γ)p=2βγ(All the probabilities are assumed to lie in the interval (0, 1)). Then P(B1)P(B3){{P\left( {{B_1}} \right)} \over {P\left( {{B_3}} \right)}}P(B3​)P(B1​)​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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