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Probability question

2017 · 8 Apr · Shift 1 · Q38
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Probability question

2017 · 8 Apr · Shift 1 · Q38

JEE MainMathematicsProbabilityMCQ+4 / −1
An unbiased coin is tossed eight times. The probability of obtaining at least one head and at least one tail is :
  1. A
    255256{{255} \over {256}}256255​
  2. B
    127128{{127} \over {128}}128127​
  3. C
    6364{{63} \over {64}}6463​
  4. D
    12{{1} \over {2}}21​
View written solutionFree

Correct answer: B

  1. Total number of outcomes

    Since an unbiased coin is tossed 888 times, each toss has 222 possible outcomes.

    Hence total outcomes: 28=2562^8 = 25628=256

  2. Required event

    We need the probability of getting at least one head and at least one tail.

    This means we exclude only these two cases:

    • all heads
    • all tails
  3. Count unfavorable outcomes

    • All heads: 111 outcome
    • All tails: 111 outcome

    So total unfavorable outcomes: 1+1=21+1=21+1=2

  4. Count favorable outcomes

    256−2=254256-2=254256−2=254

  5. Compute probability

    P(at least one head and at least one tail)=254256=127128P(\text{at least one head and at least one tail}) = \frac{254}{256} = \frac{127}{128}P(at least one head and at least one tail)=256254​=128127​

  6. Option matching

    127128\frac{127}{128}128127​ corresponds to Option B.

Therefore, the correct answer is B.

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