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Limits Continuity and Differentiability question

2024 · 5 Apr · Shift 2 · Q56

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JEE Main
Mathematics
Limits Continuity and Differentiability
2024 · 5 Apr · Shift 2 · Q56

Limits Continuity and Differentiability question

2024 · 5 Apr · Shift 2 · Q56

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1

Let

\mathrm{a}\gt 0

be a root of the equation

2 x^2+x-2=0

. If

\lim_{x \rightarrow \frac{1}{a}} \frac{16\left(1-\cos \left(2+x-2 x^2\right)\right)}{(1-a x)^2}=\alpha+\beta \sqrt{17}

, where

\alpha, \beta \in Z

, then

\alpha+\beta

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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