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Limits Continuity and Differentiability question

2024 · 9 Apr · Shift 1 · Q53
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  5. /2024 · 9 Apr · Shift 1 · Q53

Limits Continuity and Differentiability question

2024 · 9 Apr · Shift 1 · Q53

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
Let f:(0,π)→Rf:(0, \pi) \rightarrow \mathbf{R}f:(0,π)→R be a function given by f(x)={(87)tan⁡8xtan⁡7x,0<x<π2a−8,x=π2(1+∣cot⁡x∣)ba∣tan⁡x∣,π2<x<πf(x)=\left\{\begin{array}{cc}\left(\frac{8}{7}\right)^{\frac{\tan 8 x}{\tan 7 x}}, & 0\lt x\lt \frac{\pi}{2} \\ \mathrm{a}-8, & x=\frac{\pi}{2} \\ (1+|\cot x|)^{\frac{\mathrm{b}}{\mathrm{a}}|\tan x|}, & \frac{\pi}{2} \lt x \lt \pi\end{array}\right.f(x)=⎩⎨⎧​(78​)tan7xtan8x​,a−8,(1+∣cotx∣)ab​∣tanx∣,​0<x<2π​x=2π​2π​<x<π​ where a,b∈Z\mathrm{a}, \mathrm{b} \in \mathbf{Z}a,b∈Z. If fff is continuous at x=π2x=\frac{\pi}{2}x=2π​, then a2+b2\mathrm{a}^2+\mathrm{b}^2a2+b2 is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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