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Limits Continuity and Differentiability question

2024 · 4 Apr · Shift 1 · Q54
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  5. /2024 · 4 Apr · Shift 1 · Q54

Limits Continuity and Differentiability question

2024 · 4 Apr · Shift 1 · Q54

JEE MainMathematicsLimits Continuity and DifferentiabilityNumerical+4 / −1
If lim⁡x→1(5x+1)1/3−(x+5)1/3(2x+3)1/2−(x+4)1/2=m5n(2n)2/3\lim_{x \rightarrow 1} \frac{(5 x+1)^{1 / 3}-(x+5)^{1 / 3}}{(2 x+3)^{1 / 2}-(x+4)^{1 / 2}}=\frac{\mathrm{m} \sqrt{5}}{\mathrm{n}(2 \mathrm{n})^{2 / 3}}x→1lim​(2x+3)1/2−(x+4)1/2(5x+1)1/3−(x+5)1/3​=n(2n)2/3m5​​, where gcd⁡(m,n)=1\operatorname{gcd}(\mathrm{m}, \mathrm{n})=1gcd(m,n)=1, then 8 m+12n8 \mathrm{~m}+12 \mathrm{n}8 m+12n is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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