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Indefinite Integrals question

2022 · 26 Jul · Shift 2 · Q32
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  5. /2022 · 26 Jul · Shift 2 · Q32

Indefinite Integrals question

2022 · 26 Jul · Shift 2 · Q32

JEE MainMathematicsIndefinite IntegralsMCQ+4 / −1
 The integral ∫(1−13)(cos⁡x−sin⁡x)(1+23sin⁡2x)dx is equal to \text { The integral } \int \frac{\left(1-\frac{1}{\sqrt{3}}\right)(\cos x-\sin x)}{\left(1+\frac{2}{\sqrt{3}} \sin 2 x\right)} d x \text { is equal to } The integral ∫(1+3​2​sin2x)(1−3​1​)(cosx−sinx)​dx is equal to 
  1. A
    12log⁡e∣tan⁡(x2+π12)tan⁡(x2+π6)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{12}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}\right|+C21​loge​​tan(2x​+6π​)tan(2x​+12π​)​​+C
  2. B
    12log⁡e∣tan⁡(x2+π6)tan⁡(x2+π3)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{3}\right)}\right|+C21​loge​​tan(2x​+3π​)tan(2x​+6π​)​​+C
  3. C
    log⁡e∣tan⁡(x2+π6)tan⁡(x2+π12)∣+C\log _{e}\left|\frac{\tan \left(\frac{x}{2}+\frac{\pi}{6}\right)}{\tan \left(\frac{x}{2}+\frac{\pi}{12}\right)}\right|+Cloge​​tan(2x​+12π​)tan(2x​+6π​)​​+C
  4. D
    12log⁡e∣tan⁡(x2−π12)tan⁡(x2−π6)∣+C\frac{1}{2} \log _{e}\left|\frac{\tan \left(\frac{x}{2}-\frac{\pi}{12}\right)}{\tan \left(\frac{x}{2}-\frac{\pi}{6}\right)}\right|+C21​loge​​tan(2x​−6π​)tan(2x​−12π​)​​+C
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