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Hyperbola question

2024 · 31 Jan · Shift 1 · Q57

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JEE Main
Mathematics
Hyperbola
2024 · 31 Jan · Shift 1 · Q57

Hyperbola question

2024 · 31 Jan · Shift 1 · Q57

JEE MainMathematicsHyperbolaNumerical+4 / −1

Let the foci and length of the latus rectum of an ellipse

\frac{x^2}{a^2}+\frac{y^2}{b^2}=1, a>b b e( \pm 5,0)

and

\sqrt{50}

, respectively. Then, the square of the eccentricity of the hyperbola

\frac{x^2}{b^2}-\frac{y^2}{a^2 b^2}=1

equals

Numerical answer

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