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Hyperbola question

2022 · 24 Jun · Shift 2 · Q44
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  5. /2022 · 24 Jun · Shift 2 · Q44

Hyperbola question

2022 · 24 Jun · Shift 2 · Q44

JEE MainMathematicsHyperbolaNumerical+4 / −1
Let the hyperbola H:x2a2−y2=1H:{{{x^2}} \over {{a^2}}} - {y^2} = 1H:a2x2​−y2=1 and the ellipse E:3x2+4y2=12E:3{x^2} + 4{y^2} = 12E:3x2+4y2=12 be such that the length of latus rectum of H is equal to the length of latus rectum of E. If eH{e_H}eH​ and eE{e_E}eE​ are the eccentricities of H and E respectively, then the value of 12(eH2+eE2)12\left( {e_H^2 + e_E^2} \right)12(eH2​+eE2​) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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