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Hyperbola question

2023 · 6 Apr · Shift 2 · Q38
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  5. /2023 · 6 Apr · Shift 2 · Q38

Hyperbola question

2023 · 6 Apr · Shift 2 · Q38

JEE MainMathematicsHyperbolaNumerical+4 / −1
Let the eccentricity of an ellipse x2a2+y2b2=1\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1a2x2​+b2y2​=1 is reciprocal to that of the hyperbola 2x2−2y2=12 x^{2}-2 y^{2}=12x2−2y2=1. If the ellipse intersects the hyperbola at right angles, then square of length of the latus-rectum of the ellipse is ‾\underline{\hspace{2cm}}​.
Numerical answer
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