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Hyperbola question

2023 · 25 Jan · Shift 2 · Q29

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JEE Main
Mathematics
Hyperbola
2023 · 25 Jan · Shift 2 · Q29

Hyperbola question

2023 · 25 Jan · Shift 2 · Q29

JEE MainMathematicsHyperbolaMCQ+4 / −1

Let T and C respectively be the transverse and conjugate axes of the hyperbola

16{x^2} - {y^2} + 64x + 4y + 44 = 0

. Then the area of the region above the parabola

{x^2} = y + 4

, below the transverse axis T and on the right of the conjugate axis C is :

A
$4\sqrt 6 - {{28} \over 3}$
B
$4\sqrt 6 - {{44} \over 3}$
C
$4\sqrt 6 + {{28} \over 3}$
D
$4\sqrt 6 + {{44} \over 3}$

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