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Hyperbola question

2024 · 30 Jan · Shift 1 · Q56

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Mathematics
Hyperbola
2024 · 30 Jan · Shift 1 · Q56

Hyperbola question

2024 · 30 Jan · Shift 1 · Q56

JEE MainMathematicsHyperbolaNumerical+4 / −1

Let the latus rectum of the hyperbola

\frac{x^2}{9}-\frac{y^2}{b^2}=1

subtend an angle of

\frac{\pi}{3}

at the centre of the hyperbola. If

\mathrm{b}^2

is equal to

\frac{l}{\mathrm{~m}}(1+\sqrt{\mathrm{n}})

, where

l

and

\mathrm{m}

are co-prime numbers, then

\mathrm{l}^2+\mathrm{m}^2+\mathrm{n}^2

is equal to

\underline{\hspace{2cm}}

.

Numerical answer

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