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Functions question

2021 · 20 Jul · Shift 2 · Q29
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  5. /2021 · 20 Jul · Shift 2 · Q29

Functions question

2021 · 20 Jul · Shift 2 · Q29

JEE MainMathematicsFunctionsMCQ+4 / −1
Let f:R−{α6}→Rf:R - \left\{ {{\alpha \over 6}} \right\} \to Rf:R−{6α​}→R be defined by f(x)=5x+36x−αf(x) = {{5x + 3} \over {6x - \alpha }}f(x)=6x−α5x+3​. Then the value of α\alphaα for which (fof)(x) = x, for all x∈R−{α6}x \in R - \left\{ {{\alpha \over 6}} \right\}x∈R−{6α​}, is :
  1. A
    No such α\alphaα exists
  2. B
    5
  3. C
    8
  4. D
    6
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