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Functions question

2021 · 24 Feb · Shift 2 · Q37
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  5. /2021 · 24 Feb · Shift 2 · Q37

Functions question

2021 · 24 Feb · Shift 2 · Q37

JEE MainMathematicsFunctionsNumerical+4 / −1
If a + α\alphaα= 1, b +β\betaβ= 2 and af(x)+αf(1x)=bx+βx,xe0af(x) + \alpha f\left( {{1 \over x}} \right) = bx + {\beta \over x},x e 0af(x)+αf(x1​)=bx+xβ​,xe0, then the value of the expression f(x)+f(1x)x+1x{{f(x) + f\left( {{1 \over x}} \right)} \over {x + {1 \over x}}}x+x1​f(x)+f(x1​)​ is ‾\underline{\hspace{2cm}}​.
Numerical answer
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