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Ellipse question

2025 · 22 Jan · Shift 2 · Q45

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JEE Main
Mathematics
Ellipse
2025 · 22 Jan · Shift 2 · Q45

Ellipse question

2025 · 22 Jan · Shift 2 · Q45

JEE MainMathematicsEllipseMCQ+4 / −1

Let

\mathrm{E}: \frac{x^2}{\mathrm{a}^2}+\frac{y^2}{\mathrm{~b}^2}=1, \mathrm{a}\gt \mathrm{b}

and

\mathrm{H}: \frac{x^2}{\mathrm{~A}^2}-\frac{y^2}{\mathrm{~B}^2}=1

. Let the distance between the foci of E and the foci of

H

be

2 \sqrt{3}

. If

a-A=2

, and the ratio of the eccentricities of

E

and

H

is

\frac{1}{3}

, then the sum of the lengths of their latus rectums is equal to :

A
10
B
7
C
9
D
8

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