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Ellipse question

2025 · 29 Jan · Shift 1 · Q30
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  5. /2025 · 29 Jan · Shift 1 · Q30

Ellipse question

2025 · 29 Jan · Shift 1 · Q30

JEE MainMathematicsEllipseMCQ+4 / −1
Let the ellipse E1:x2a2+y2b2=1E_1: \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1E1​:a2x2​+b2y2​=1, a>ba \gt ba>b and E2:x2A2+y2B2=1E_2: \frac{x^2}{A^2} + \frac{y^2}{B^2} = 1E2​:A2x2​+B2y2​=1, A<BA \lt BA<B have same eccentricity 13\frac{1}{\sqrt{3}}3​1​. Let the product of their lengths of latus rectums be 323\frac{32}{\sqrt{3}}3​32​ and the distance between the foci of E1E_1E1​ be 4. If E1E_1E1​ and E2E_2E2​ meet at A, B, C and D, then the area of the quadrilateral ABCD equals :
  1. A
    2465\frac{24\sqrt{6}}{5}5246​​
  2. B
    1865\frac{18\sqrt{6}}{5}5186​​
  3. C
    666\sqrt{6}66​
  4. D
    1265\frac{12\sqrt{6}}{5}5126​​
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