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Differential Equations question

2024 · 31 Jan · Shift 1 · Q37
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  5. /2024 · 31 Jan · Shift 1 · Q37

Differential Equations question

2024 · 31 Jan · Shift 1 · Q37

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation dydx=(tan⁡x)+ysin⁡x(sec⁡x−sin⁡xtan⁡x),x∈(0,π2)\frac{d y}{d x}=\frac{(\tan x)+y}{\sin x(\sec x-\sin x \tan x)}, x \in\left(0, \frac{\pi}{2}\right)dxdy​=sinx(secx−sinxtanx)(tanx)+y​,x∈(0,2π​) satisfying the condition y(π4)=2y\left(\frac{\pi}{4}\right)=2y(4π​)=2. Then, y(π3)y\left(\frac{\pi}{3}\right)y(3π​) is
  1. A
    3(2+log⁡e3)\sqrt{3}\left(2+\log _e 3\right)3​(2+loge​3)
  2. B
    3(1+2log⁡e3)\sqrt{3}\left(1+2 \log _e 3\right)3​(1+2loge​3)
  3. C
    3(2+log⁡e3)\sqrt{3}\left(2+\log _e \sqrt{3}\right)3​(2+loge​3​)
  4. D
    32(2+log⁡e3)\frac{\sqrt{3}}{2}\left(2+\log _e 3\right)23​​(2+loge​3)
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