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Differential Equations question

2023 · 1 Feb · Shift 1 · Q34
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  5. /2023 · 1 Feb · Shift 1 · Q34

Differential Equations question

2023 · 1 Feb · Shift 1 · Q34

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
If y=y(x)y=y(x)y=y(x) is the solution curve of the differential equation dydx+ytan⁡x=xsec⁡x,0≤x≤π3,y(0)=1\frac{d y}{d x}+y \tan x=x \sec x, 0 \leq x \leq \frac{\pi}{3}, y(0)=1dxdy​+ytanx=xsecx,0≤x≤3π​,y(0)=1, then y(π6)y\left(\frac{\pi}{6}\right)y(6π​) is equal to
  1. A
    π12−32log⁡e(23e)\frac{\pi}{12}-\frac{\sqrt{3}}{2} \log _{e}\left(\frac{2 \sqrt{3}}{e}\right)12π​−23​​loge​(e23​​)
  2. B
    π12+32log⁡e(23e)\frac{\pi}{12}+\frac{\sqrt{3}}{2} \log _{e}\left(\frac{2 \sqrt{3}}{e}\right)12π​+23​​loge​(e23​​)
  3. C
    π12+32log⁡e(2e3)\frac{\pi}{12}+\frac{\sqrt{3}}{2} \log _{e}\left(\frac{2}{e \sqrt{3}}\right)12π​+23​​loge​(e3​2​)
  4. D
    π12−32log⁡e(2e3)\frac{\pi}{12}-\frac{\sqrt{3}}{2} \log _{e}\left(\frac{2}{e \sqrt{3}}\right)12π​−23​​loge​(e3​2​)
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