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Differential Equations question

2023 · 1 Feb · Shift 2 · Q39
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  5. /2023 · 1 Feb · Shift 2 · Q39

Differential Equations question

2023 · 1 Feb · Shift 2 · Q39

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let αx=exp⁡(xβyγ)\alpha x=\exp \left(x^{\beta} y^{\gamma}\right)αx=exp(xβyγ) be the solution of the differential equation 2x2y dy−(1−xy2)dx=0,x>0,y(2)=log⁡e22 x^{2} y \mathrm{~d} y-\left(1-x y^{2}\right) \mathrm{d} x=0, x \gt 0,y(2)=\sqrt{\log _{e} 2}2x2y dy−(1−xy2)dx=0,x>0,y(2)=loge​2​. Then α+β−γ\alpha+\beta-\gammaα+β−γ equals :
  1. A
    1
  2. B
    0
  3. C
    3
  4. D
    −1-1−1
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