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Differential Equations question

2023 · 6 Apr · Shift 1 · Q36
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  5. /2023 · 6 Apr · Shift 1 · Q36

Differential Equations question

2023 · 6 Apr · Shift 1 · Q36

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let y=y(x)y=y(x)y=y(x) be a solution of the differential equation (xcos⁡x)dy+(xysin⁡x+ycos⁡x−1)dx=0,0<x<π2(x \cos x) d y+(x y \sin x+y \cos x-1) d x=0,0 \lt x \lt \frac{\pi}{2}(xcosx)dy+(xysinx+ycosx−1)dx=0,0<x<2π​. If π3y(π3)=3\frac{\pi}{3} y\left(\frac{\pi}{3}\right)=\sqrt{3}3π​y(3π​)=3​, then ∣π6y′′(π6)+2y′(π6)∣\left|\frac{\pi}{6} y^{\prime \prime}\left(\frac{\pi}{6}\right)+2 y^{\prime}\left(\frac{\pi}{6}\right)\right|​6π​y′′(6π​)+2y′(6π​)​ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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