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Differential Equations question

2024 · 27 Jan · Shift 2 · Q60
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  5. /2024 · 27 Jan · Shift 2 · Q60

Differential Equations question

2024 · 27 Jan · Shift 2 · Q60

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
If the solution curve, of the differential equation dy dx=x+y−2x−y\frac{\mathrm{d} y}{\mathrm{~d} x}=\frac{x+y-2}{x-y} dxdy​=x−yx+y−2​ passing through the point (2,1)(2,1)(2,1) is tan⁡−1(y−1x−1)−1βlog⁡e(α+(y−1x−1)2)=log⁡e∣x−1∣\tan ^{-1}\left(\frac{y-1}{x-1}\right)-\frac{1}{\beta} \log _{\mathrm{e}}\left(\alpha+\left(\frac{y-1}{x-1}\right)^2\right)=\log _{\mathrm{e}}|x-1|tan−1(x−1y−1​)−β1​loge​(α+(x−1y−1​)2)=loge​∣x−1∣, then 5β+α5 \beta+\alpha5β+α is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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