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Differential Equations question

2024 · 4 Apr · Shift 1 · Q43

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JEE Main
Mathematics
Differential Equations
2024 · 4 Apr · Shift 1 · Q43

Differential Equations question

2024 · 4 Apr · Shift 1 · Q43

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

If the solution

y=y(x)

of the differential equation

(x^4+2 x^3+3 x^2+2 x+2) \mathrm{d} y-(2 x^2+2 x+3) \mathrm{d} x=0

satisfies

y(-1)=-\frac{\pi}{4}

, then

y(0)

is equal to :

A
$-\frac{\pi}{12}$
B
$\frac{\pi}{2}$
C
0
D
$\frac{\pi}{4}$

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