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Differential Equations question

2024 · 1 Feb · Shift 2 · Q54
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  5. /2024 · 1 Feb · Shift 2 · Q54

Differential Equations question

2024 · 1 Feb · Shift 2 · Q54

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
If dx dy=1+x−y2y,x(1)=1\frac{\mathrm{d} x}{\mathrm{~d} y}=\frac{1+x-y^2}{y}, x(1)=1 dydx​=y1+x−y2​,x(1)=1, then 5x(2)5 x(2)5x(2) is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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