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Differential Equations question

2024 · 4 Apr · Shift 2 · Q41

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JEE Main
Mathematics
Differential Equations
2024 · 4 Apr · Shift 2 · Q41

Differential Equations question

2024 · 4 Apr · Shift 2 · Q41

JEE MainMathematicsDifferential EquationsMCQ+4 / −1

Let

y=y(x)

be the solution of the differential equation

(x^2+4)^2 d y+(2 x^3 y+8 x y-2) d x=0

. If

y(0)=0

, then

y(2)

is equal to

A
$2 \pi$
B
$\frac{\pi}{8}$
C
$\frac{\pi}{16}$
D
$\frac{\pi}{32}$

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