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Differential Equations question

2024 · 4 Apr · Shift 2 · Q57
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  5. /2024 · 4 Apr · Shift 2 · Q57

Differential Equations question

2024 · 4 Apr · Shift 2 · Q57

JEE MainMathematicsDifferential EquationsNumerical+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution of the differential equation (x+y+2)2dx=dy,y(0)=−2(x+y+2)^2 d x=d y, y(0)=-2(x+y+2)2dx=dy,y(0)=−2. Let the maximum and minimum values of the function y=y(x)y=y(x)y=y(x) in [0,π3]\left[0, \frac{\pi}{3}\right][0,3π​] be α\alphaα and β\betaβ, respectively. If (3α+π)2+β2=γ+δ3,γ,δ∈Z(3 \alpha+\pi)^2+\beta^2=\gamma+\delta \sqrt{3}, \gamma, \delta \in \mathbb{Z}(3α+π)2+β2=γ+δ3​,γ,δ∈Z, then γ+δ\gamma+\deltaγ+δ equals ‾\underline{\hspace{2cm}}​.
Numerical answer
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