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Differential Equations question

2023 · 11 Apr · Shift 1 · Q29
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  5. /2023 · 11 Apr · Shift 1 · Q29

Differential Equations question

2023 · 11 Apr · Shift 1 · Q29

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be a solution curve of the differential equation. (1−x2y2)dx=ydx+xdy\left(1-x^{2} y^{2}\right) d x=y d x+x d y(1−x2y2)dx=ydx+xdy. If the line x=1x=1x=1 intersects the curve y=y(x)y=y(x)y=y(x) at y=2y=2y=2 and the line x=2x=2x=2 intersects the curve y=y(x)y=y(x)y=y(x) at y=αy=\alphay=α, then a value of α\alphaα is :
  1. A
    1+3e22(3e2−1)\frac{1+3 e^{2}}{2\left(3 e^{2}-1\right)}2(3e2−1)1+3e2​
  2. B
    3e22(3e2−1)\frac{3 e^{2}}{2\left(3 e^{2}-1\right)}2(3e2−1)3e2​
  3. C
    1−3e22(3e2+1)\frac{1-3 e^{2}}{2\left(3 e^{2}+1\right)}2(3e2+1)1−3e2​
  4. D
    3e22(3e2+1)\frac{3 e^{2}}{2\left(3 e^{2}+1\right)}2(3e2+1)3e2​
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