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Differential Equations question

2008 · Shift 0 · Q35
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  5. /2008 · Shift 0 · Q35

Differential Equations question

2008 · Shift 0 · Q35

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
The solution of the differential equation dydx=x+yx{{dy} \over {dx}} = {{x + y} \over x}dxdy​=xx+y​ satisfying the condition y(1)=1y(1)=1y(1)=1 is :
  1. A
    y=ln⁡x+xy = \ln x + xy=lnx+x
  2. B
    y=xln⁡x+x2y = x\ln x + {x^2}y=xlnx+x2
  3. C
    y=xe(x−1) y = x{e^{\left( {x - 1} \right)}}\,y=xe(x−1)
  4. D
    y=x ln⁡x+xy = x\,\ln x + xy=xlnx+x
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