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Differential Equations question

2003 · Shift 0 · Q87
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Differential Equations question

2003 · Shift 0 · Q87

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
The degree and order of the differential equation of the family of all parabolas whose axis is xxx-axis, are respectively.
  1. A
    2,32, 32,3
  2. B
    2,12,12,1
  3. C
    1,21,21,2
  4. D
    3,2.3,2.3,2.
View written solutionFree

Correct answer: DEGREE = 1, ORDER = 3, QUESTION/OPTIONS LIKELY CONTAIN AN ERROR SINCE (1,3) IS NOT LISTED

  1. Write the family of parabolas whose axis is the xxx-axis

A parabola with axis along the xxx-axis has standard form

(y−k)2=4a(x−h),(y-k)^2 = 4a(x-h),(y−k)2=4a(x−h),

where a,h,ka,h,ka,h,k are arbitrary constants.

So this family contains 3 arbitrary constants: a,h,ka,h,ka,h,k.

  1. Find the order of the differential equation

In general, eliminating 333 arbitrary constants requires differentiating enough times, leading to a differential equation of order 333.

Hence, the order is

3.3.3.
  1. Check the degree

The degree is the power of the highest order derivative after removing radicals/fractions in derivatives.

For this family, after elimination, the highest derivative appears polynomially and linearly in the final equation, so the degree is

1.1.1.

Thus, the differential equation has:

  • order =3=3=3
  • degree =1=1=1
  1. Compare with options

The pair (degree,order)(\text{degree},\text{order})(degree,order) is

(1,3).(1,3).(1,3).

But none of the given options is (1,3)(1,3)(1,3).

So the listed options appear inconsistent.

  1. Compare with stored correct answer

Stored correct answer is C, i.e. (1,2)(1,2)(1,2).

This does not match the derived result (1,3)(1,3)(1,3).

Therefore, the stored answer seems incorrect.

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