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Differential Equations question

2025 · 7 Apr · Shift 1 · Q32
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  5. /2025 · 7 Apr · Shift 1 · Q32

Differential Equations question

2025 · 7 Apr · Shift 1 · Q32

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let y=y(x)y=y(x)y=y(x) be the solution curve of the differential equation x(x2+ex)dy+(ex(x−2)y−x3)dx=0,x>0x\left(x^2+e^x\right) d y+\left(\mathrm{e}^x(x-2) y-x^3\right) \mathrm{d} x=0, x\gt 0x(x2+ex)dy+(ex(x−2)y−x3)dx=0,x>0, passing through the point (1,0)(1,0)(1,0). Then y(2)y(2)y(2) is equal to :
  1. A
    22+e2\frac{2}{2+e^2}2+e22​
  2. B
    44−e2\frac{4}{4-e^2}4−e24​
  3. C
    44+e2\frac{4}{4+e^2}4+e24​
  4. D
    22−e2\frac{2}{2-e^2}2−e22​
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