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Differential Equations question

2025 · 3 Apr · Shift 1 · Q39
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  5. /2025 · 3 Apr · Shift 1 · Q39

Differential Equations question

2025 · 3 Apr · Shift 1 · Q39

JEE MainMathematicsDifferential EquationsMCQ+4 / −1
Let ggg be a differentiable function such that ∫0xg(t)dt=x−∫0xtg⁡(t)dt,x≥0\int_0^x g(t) d t=x-\int_0^x \operatorname{tg}(t) d t, x \geq 0∫0x​g(t)dt=x−∫0x​tg(t)dt,x≥0 and let y=y(x)y=y(x)y=y(x) satisfy the differential equation dydx−ytan⁡x=2(x+1)sec⁡xg(x),x∈[0,π2)\frac{d y}{d x}-y \tan x=2(x+1) \sec x g(x), x \in\left[0, \frac{\pi}{2}\right)dxdy​−ytanx=2(x+1)secxg(x),x∈[0,2π​). If y(0)=0y(0)=0y(0)=0, then y(π3)y\left(\frac{\pi}{3}\right)y(3π​) is equal to
  1. A
    4π3\frac{4 \pi}{3}34π​
  2. B
    2π3\frac{2 \pi}{3}32π​
  3. C
    2π33\frac{2 \pi}{3 \sqrt{3}}33​2π​
  4. D
    4π33\frac{4 \pi}{3 \sqrt{3}}33​4π​
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