JEE MainMathematicsDefinite IntegrationNumerical+4 / −1If the shortest distance between the lines x+22=y+33=z−54\frac{x+2}{2}=\frac{y+3}{3}=\frac{z-5}{4}2x+2=3y+3=4z−5 and x−31=y−2−3=z+42\frac{x-3}{1}=\frac{y-2}{-3}=\frac{z+4}{2}1x−3=−3y−2=2z+4 is 3835k\frac{38}{3 \sqrt{5}} \mathrm{k}3538k, and ∫0k[x2]dx=α−α\int\limits_0^{\mathrm{k}}\left[x^2\right] \mathrm{d} x=\alpha-\sqrt{\alpha}0∫k[x2]dx=α−α, where [x][x][x] denotes the greatest integer function, then 6α36 \alpha^36α3 is equal to ‾\underline{\hspace{2cm}}.Numerical answerAttempt in chatSharePreviousNextMore from Definite IntegrationIf ∫04π1+sinxcosxsin2x dx=a1loge(3a)+b3π, where a,b∈N, then a+b…2024 · NumericalLet f(x)=∫0x(t+sin(1−et))dt,x∈R. Then, limx→0x3f(x) is equal to2024 · MCQIf the value of the integral −1∫11+3xcosαxdx is π2.Then, a value of α is2024 · MCQThe integral 0∫π/43sinx+5cosx136sinx dx is equal to :2024 · MCQThe value of ∫−ππ1+cos2y2y(1+siny)dy is :2024 · MCQLet β(m,n)=0∫1xm−1(1−x)n−1 dx, m,n>0. If 0∫1(1−x10)20 dx=a×β(b,c)…2024 · MCQIf f(t)=0∫π1−cos2tsin2x2x dx,0<t<π, then the value of 0∫2πf(t)π2dt equals .2024 · Numerical0∫π/4(cos3x+sin3x)2cos2xsin2xdx is equal to2024 · MCQ