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Definite Integration question

2024 · 5 Apr · Shift 2 · Q57
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  5. /2024 · 5 Apr · Shift 2 · Q57

Definite Integration question

2024 · 5 Apr · Shift 2 · Q57

JEE MainMathematicsDefinite IntegrationNumerical+4 / −1
If f(t)=∫0π2x dx1−cos⁡2tsin⁡2x,0<t<πf(t)=\int\limits_0^\pi \frac{2 x \mathrm{~d} x}{1-\cos^2 \mathrm{t} \sin^2 x}, 0\lt \mathrm{t}\lt \pif(t)=0∫π​1−cos2tsin2x2x dx​,0<t<π, then the value of ∫0π2π2dtf(t)\int\limits_0^{\frac{\pi}{2}} \frac{\pi^2 \mathrm{dt}}{f(\mathrm{t})}0∫2π​​f(t)π2dt​ equals ‾\underline{\hspace{2cm}}​.
Numerical answer
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