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Definite Integration question

2021 · 27 Jul · Shift 2 · Q39
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  5. /2021 · 27 Jul · Shift 2 · Q39

Definite Integration question

2021 · 27 Jul · Shift 2 · Q39

JEE MainMathematicsDefinite IntegrationNumerical+4 / −1
If ∫0π(sin⁡3x)e−sin⁡2xdx=α−βe∫01tetdt\int_0^\pi {({{\sin }^3}x){e^{ - {{\sin }^2}x}}dx = \alpha - {\beta \over e}\int_0^1 {\sqrt t {e^t}dt} }∫0π​(sin3x)e−sin2xdx=α−eβ​∫01​t​etdt, then α\alphaα+β\betaβ is equal to ‾\underline{\hspace{2cm}}​.
Numerical answer
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